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Iift 2012 Question 22

This is a detailed step-by-step solution for Iift 2012 Question 22. Understand the concept, common mistakes, and expert tips to solve similar questions in IIFT exam.

IIFT 2012

Explanation:
Let us start by putting the value of x.
When x = 1,

7x−1 + 11x−1 = 2
When x=2,

7x−1 + 11x−1 = 17

When x=3,

7x−1 + 11x−1 = 170
When x=4,

7x−1 + 11x−1 = 1547
As we can see 7x−1 + 11x−1 is an increasing function and the only value that satisfies 7x−1 + 11x−1 = 170 is x=3
Thus, the given equation has only 1 solution.
Hence, option B is the correct answer.

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