Iift 2012 Question 22
This is a detailed step-by-step solution for Iift 2012 Question 22. Understand the concept, common mistakes, and expert tips to solve similar questions in IIFT exam.
IIFT 2012
Explanation:
Let us start by putting the value of x.
When x = 1,
7x−1 + 11x−1 = 2
When x=2,
7x−1 + 11x−1 = 17
When x=3,
7x−1 + 11x−1 = 170
When x=4,
7x−1 + 11x−1 = 1547
As we can see 7x−1 + 11x−1 is an increasing function and the only value that satisfies 7x−1 + 11x−1 = 170 is x=3
Thus, the given equation has only 1 solution.
Hence, option B is the correct answer.
