XAT 2015 Question 71
This is a detailed step-by-step solution for XAT 2015 Question 71. Understand the concept, common mistakes, and expert tips to solve similar questions in XAT exam.
XAT
AB + BC + CD + AD = 1120 ------------Eqn(I)
PB + BC + CD + PD = 1000 -------------Eqn(II)
Subtracting eqn(II) from (I), we get :
=> AB - PB + (AD - PD) = 120
=> AB - PB + AP = 120
=> AB + AP = 120 + PB
Now, if AB = PB, => AP = 120
=> AD = 600 and BC = 480, then AB + PB + CD = 40, which is not possible (We know that BC = PD. If BC = PD = 480, then BC+PD =
960. PB + BC + CD + PD = 1000.
=> PB+CD = 40. Therefore, AB + PB+CD should be greater than 40).
Similarly, AB = AP is also not possible. Thus AP=BP
