IPMAT 2019 - Quantitative Aptitude Question 11
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IPMAT 2019 - Quantitative Aptitude
sin x + sin y = sinx cosy + cosx siny
sin x (1 – cosy) + siny = cosx siny
Squaring both sides,
sin2x (1 – cosy)2 + sin2 y + 2 sin x sin y (1 – cos y) = cos2 x sin2 y
Rearranging the terms,
2 sin x (1 – cos y) (sin x + sin y) = 0
sin x = 0, cos y = 1, sin (x + y) = 0
If sin x = 0, x = 0 ............ (1)
If cos y = 1, y = 0 ............ (2)
If sin(x + y) = 0, x + y = 0, x = - y ............(3)
Now, |x| + |y| = 1
∴ from (1), (0, 1) and (0, -1)
From (2), (1, 0) and (-1, 0)