IPMAT 2024 - Quantitative Aptitude Question 42
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IPMAT 2024 - Quantitative Aptitude
From point (2), we can conclude that C must have 8 votes each in S3 and S4, that so as up to 16.
It also means C did not get any votes in S1, S2 and S5.
It also implied that B must have win S4 and S5 constituencies as ‘A’ has won only in S1.
Now in S3 and S4, possible combination of votes A and B can be (5, 7), (7, 5) or (6, 6) in that order respectively.
By doing hit and trial, we can come to a conclusion that B must have win 11 and 12 votes in S4 and S5 respectively.
And also, it must have received 1, 5 and 6 votes in S1, S2 and S2 constituency from point (3).
From the completed table we can see, B got lower number of votes compared to A and C only in S2.