CMAT 2018 - Slot 2 Quantitative Aptitude Question 1
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Quantitative Aptitude
Probability = Expected number of outcomes/ Total number of outcomes.
Total number of outcomes we get in a single throw of two dice = 6 x 6 = 36.
Possible cases of getting 'nine' in a single throw of two dice:
dice 1 dice 2
three six.......................(1)
six three.................(2)
four five.....................(3)
five four...................(4)
So, total of 4 cases.
Possible cases of getting 'ten' in a single throw of two dice:
dice 1 dice 2
four six.......................(1)
six four.................(2)
five five.....................(3)
So, total of 3 cases.
Expected number of outcomes = Total possible cases of getting 'nine' or 'ten' in a single throw of two dice = 4 + 3 = 7 .
So, Probability = 7/36.