CMAT 2020 - Quantitative Aptitude Question 20
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Quantitative Aptitude
Taking the vowels (EA) as one letter, the given word has the letters XTR (EA), i.e., 4 letters.
These letters can be arranged in = 24 ways
The letters EA may be arranged amongst themselves in 2! = 2 ways.
Number of arrangements having vowels together = (24 × 2) = 48 ways
Total arrangements of all letters = 5! = 120 ways
=> Number of arrangements not having vowels together = (120 – 48) = 72 ways