CMAT 2022 Question 5
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CMAT 2022
Number of ways of selecting 2 red balls and 1 green ball =15C2 . 10C1
Number of ways of selecting 3 balls =25C3
Probability of selecting 2 red balls and 1 green ball = 15C2 . 10C1 / 25C3 = 21/46
Answer is option A.
