Iift 2008 Question 39
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IIFT 2008
There are 9 married couples. Therefore, there will be 9 men and 9 women. First, let us select the 2 men. 2 men can be selected in 9C2 = 36 ways. Now, the wives of these 2 men cannot be selected. Therefore, we have to select 2 women from the remaining 7 women. 2 women can be selected in 7C2 = 21 ways. We have selected 2 men and 2 women. A team should consist of one man and one woman. Therefore, the 2 teams can be formed in 2 ways. Therefore, the total number of ways in which the team can be selected is 36 x 21 x 2 = 1512. Therefore, option B is the right answer.