Iift 2008 Question 58
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IIFT 2008
Using Apollonius theorem in ?ABC, we can say that,
2(AD2 + BD2) = AB2 + AC2
In the right angle triangle ACD, DC2 = AD2 + AC2
2(DC2 − AC2 + BD2) = AB2 + AC2
3AC2 = BC2 − AB2
Therefore, option A is the correct answer.
