Iift 2009 Question 102
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IIFT 2009
first month he will have deficiency of 2000, second month he will have deficiency of 2500, Third month he will have deficiency of 3000,
and so on
He won't borrow until all of his savings (60000) gets exhausted i.e. until 60000 - (2000 + 2500 + 3000 + ........ up to nth month ) becomes
negative
i.e 60000 < ∗ n/2 x (4000 + (n − 1)500)
I.e. 1200<n*(35+5n)
i.e 240<n*(7+n)
This condition first becomes true for n=13 therefore Rashid will have to borrow from 13th month
Therefor the answer is option 'D'