Iift 2009 Question 107
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IIFT 2009
Amount of work done by A in one week = 1/6
Amount of work done by V in one week = 1/3
Amount of work done by Y in one week = 1/12
Therefore Amount of work done by A, V and Y in one week = 1/6 + 1/9 + 1/12 = 13/36
They work together for 2 weeks therefore work done in these 2 weeks is = 26/36
Amount of work remaining is = 1 - 26/36 = 10/36
Amount of work done by V and Y in one week = 1/9 + 1/12 = 7/36
If total number of weeks required to complete the work is n then only V and Y work together for (n-3) weeks
Therefore work done in these (n-3) weeks is = 7 x (n - 3) / 36
Remaining - is completed by Y in one week
Therefore 1/10 - 7 x (n - 3) / 36 = 12
Solving we get n = 4
Therefore The job would be completed in 4 weeks
Therefore our answer is option 'A'