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Iift 2009 Question 99

This is a detailed step-by-step solution for Iift 2009 Question 99. Understand the concept, common mistakes, and expert tips to solve similar questions in IIFT exam.

IIFT 2009

Top face will look like the figure shown below.

Curved surface area of the cylinder = 2 ∗ π ∗ r ∗ h
To calculate height of the cylinder in terms of 'r', we can see that traingle ADC is similar to triangle EFC.
Therefore, AD/DC = EF/FC

10/4 = h/4-r

h = 5/2(4-r)
Therefore, the curved surface area of the cylinder = 2 ∗ π ∗ r ∗ 5/2(4 −r) = 5πr(4 − r)

Hence, option B is the correct answer.

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