Iift 2010 Question 10
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IIFT 2010
Given that cost of a type of pastry is equal to the quantity bought
if x,y,z are the no. of pastries bought of each type then x2 + y2 + z2 = 211 and x+y+z = 23
Using options,
option A = 10,9,4 i.e. 100+81+16 = 197 therefore cannot be the answer
option B= 11, 9, 3 i.e. 121+81+9 = 211 Therefore is our answer
option C = 10, 8 , 5 i.e. 100+64+25 = 189 therefore cannot be the answer
option D = 11, 8, 4 i.e. 121+64+16 = 201 therefore cannot be the answer
Therefore our answer is option 'B'