Iift 2010 Question 15
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IIFT 2010
Let the capacity of the tank be 60 litres.
Capacity of the first pipe = 12 l/hr
Capacity of the second pipe = 6 l/hr
Capacity of the third pipe = 4 l/hr
In 2 hrs, first pipe fills (9 + 12) l = 21 l
In 2 hrs, second pipe fills (4.5 + 6) = 10.5 l
In 2 hrs, third pipe fills (16/3) l
In 2 hrs, tank filled = (21 + 10.5 + 5.33) l = 36.83 l
Tank left to be filled = (60 - 36.83) l = 23.17 l
Time required = (23.17/22) hr = 1.05 hrs
Total time = 3.05 hrs
log4 log4 4 = a−b 2 log4( a − b) + log4 4
log4 log4 4 = a−b log4(( a − b)2) ∗ 4
log4 4 = a−b (( a − b)2) ∗ 4
log4 4 = (( a − b)2) ∗ 4
Hence, option C is the correct answer.