Iift 2010 Question 63
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IIFT 2010
Explanation:
We know that, female population = Total population - Male population.
Therefore, the percentage increase in Female population in 1996 = $$\dfrac{(650-320) - (600-300)}{(600-300)}\times 100$$ = 10%
The percentage increase in Female population in 1999 = $$\dfrac{(750-400) - (700-380)}{(700-380)}\times 100$$ = 9.37%
The percentage increase in Female population in 2004 = $$\dfrac{(845-475) - (800-450)}{(800-450)}\times 100$$ = 5.71%
The percentage increase in Female population in 2005 = $$\dfrac{(900-480) - (845-475)}{(845-475)}\times 100$$ = 13.51%
Hence, option D is the correct answer.