Iift 2011 Question 53
This is a detailed step-by-step solution for Iift 2011 Question 53. Understand the concept, common mistakes, and expert tips to solve similar questions in IIFT exam.
IIFT 2011
Explanation:
For a number to be divisible by 3, the sum of it's digit should be a multiple of 3. This can be done in two ways. When the number are formed by using either {1, 2, 3, 4, 5} or {0, 1, 2, 4, 5}.
Total 5 digit numbers that can be formed by {1, 2, 3, 4, 5} without repetition = 5*4*3*2*1 = 120
Total 5 digit numbers that can be formed by {0, 1, 2, 4, 5} without repetition = 4*4*3*2*1 = 96
Therefore, total such number = 120 + 96 = 216. Hence, option D is the correct answer.