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Iift 2011 Question 57

This is a detailed step-by-step solution for Iift 2011 Question 57. Understand the concept, common mistakes, and expert tips to solve similar questions in IIFT exam.

IIFT 2011

Explanation:
Let ABC be the arc as shown in the figure. It is known that the diameter of the circle = 84 cm. Hence, the radius of the circle = 42 cm.

We can see that both CO and BO are equivalent to the radius of the circle. Hence, CO = 42 cm and BD = BO - OD = 42 - 21 = 21 cm.

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