Iift 2012 Question 114
This is a detailed step-by-step solution for Iift 2012 Question 114. Understand the concept, common mistakes, and expert tips to solve similar questions in IIFT exam.
IIFT 2012
Explanation:
As we can see in the 1st step the smallest number come to the 1st position from left.
In the 2nd step the largest number comes to the 2nd position from left.
In the 3rd step the 2nd smallest number come to the 3rd position from left and so on.
Thus, 319 318 746 123 15 320 78 426
Step 1:- 15 319 318 746 123 320 78 426
Step 2:- 15 746 319 318 123 320 78 426
Step 3:- 15 746 78 319 318 123 320 426
Step 4:- 15 746 78 426 319 318 123 320
Step 5:- 15 746 78 426 123 319 318 320
Step 6:- 15 746 78 426 123 320 319 318
Step 7:- 15 746 78 426 123 320 318 319
Thus, 7 steps will be required to get the output.
Hence, option C is the correct answer.