How to solve Iift 2021 - 23rd Dec Question 23?

This question can be solved by applying the core concept explained in the solution above, followed by step-by-step calculation and elimination of options.

Which concept is tested in this question?

This question tests fundamental concepts commonly asked in IIFT exams.

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Iift 2021 - 23rd Dec Question 23

This is a detailed step-by-step solution for Iift 2021 - 23rd Dec Question 23. Understand the concept, common mistakes, and expert tips to solve similar questions in IIFT exam.

IIFT 2021 (23rd Dec)

Distance of point (-1.25 + 200√2, 8.75) from lines y-x=10 and x+y=15/2
Distance from y-x=10 is |1.25 - 200√2, +8.75 - 10| = 200

√1 + √1
Distance from x+y=15/2 is |-1.25 + 200√2, +8.75 - 7.5| = 200

√1 + √1

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