How to solve XAT 2013 Question 69?

This question can be solved by applying the core concept explained in the solution above, followed by step-by-step calculation and elimination of options.

Which concept is tested in this question?

This question tests fundamental concepts commonly asked in XAT exams.

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XAT 2013 Question 69

This is a detailed step-by-step solution for XAT 2013 Question 69. Understand the concept, common mistakes, and expert tips to solve similar questions in XAT exam.

XAT

Let '100x' be the number of students who joined XCRI last year.
Let 'a', 'b', 'c' and d be the number of students who play 1 game, 2 games, 3 games and 4 games respectively.
Therefore,
a+b+c+d = 100x ... (1)
a+2b+3c+4d = 70x+75x+80x+85x
a+2b+3c+4d = 310x ... (2)
By equation (2) - (1)
b+2c+3d = 210x

We have to minimize 'd' for that we have to maximize c. But c ≤ 100x
At cmax = 90x, dmin = 10x
Therefore, we can say that the minimum percentage of students who play all four games = 10%.

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