XAT 2018 Question 41
This is a detailed step-by-step solution for XAT 2018 Question 41. Understand the concept, common mistakes, and expert tips to solve similar questions in XAT exam.
XAT
T102: Kharagpur to Howrah station (9:05 - 11:10) --> Delivery (11:11 - 12:40) --> Howrah to Jamshedpur station (14:30 - 17:45) via T204-- > Delivery (18:35). Thus, a total of 9hr 30mins.
T103: Kharagpur to Howrah station (12:05 - 14:30) --> Delivery (14:31 - 16:00) --> Howrah to Jamshedpur station (16:00 - 20:00) via T205 --> Delivery (20:50). Thus, a total of 8hr 45mins.
T202: Kharagpur to Jamshedpur station (10:40 - 12:35) --> Delivery (12:35 - 14:05) --> Jamshedpur to Howrah station (15:00 - 18:00) via
T104 --> Delivery (18:50). Thus, a total of 8hr 10mins.
T203: Kharagpur to Jamshedpur station (12:15 - 14:00) --> Delivery (14:01 - 15:30) --> Jamshedpur to Howrah station (17:00 - 20:30) via
T105 --> Delivery (20:30 - 21:20). Thus, a total of 9hr 05mins.
Thus, T202 requires the least amount of time.
Hence, option C is the answer.