XAT 2020 Question 59
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XAT
Given, z/4 > x/6 > y/5 ...(i)
and (x+y+z)/15= 2*y/5 => x+z=5y
The value of y can only be 1.
=> x+z=5.
If z = 1, then z/4 is less than x/6.
If z = 2, then z/4 is equal to x/6.
If z = 4 or 5 then y/5 is greater than x/6.
The only possible value to satisfy (i) condition is z=3. and x=2.