XAT 2021 - Dm Question 20
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QADI
Since x2 - y2 = 20 and x, y, z are positive integers the only values possible are x = 6 and y = 4.
y3 - 2x2 - 4x ≥ - 12
Keeping the values of x and y, we get z ≤ 1
=> z = 1
