CAT 2023 Slot 1 - DILR

1. F&A = 9 members; M&S = 7 members; O&Q = 5 members; B&H = 3 members
2. Only one of the candidates was from O&Q.
3. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
4. There cannot be more than two candidates from a single department.
5. A candidate cannot vote for himself/herself.
6. Faculty members cannot vote for a candidate from their own department.
7. Prof. P = 3 votes, Prof. Q = 14 votes, Prof. R = 6 votes and Prof. S = 1.
8. P voted for R, Q voted for S; R voted for Q and S voted for P.
Each professor got one professor vote.

1. Only one of the candidates was from O&Q.
2. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
3. There cannot be more than two candidates from a single department. 
4. Faculty members cannot vote for a candidate from their own department. 
5. P voted for R, Q voted for S; R voted for Q and S voted for P.

1. F&A = 9 members; M&S = 7 members; O&Q = 5 members; B&H = 3 members
2. Only one of the candidates was from O&Q.
3. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
4. There cannot be more than two candidates from a single department.
5. A candidate cannot vote for himself/herself.
6. Faculty members cannot vote for a candidate from their own department.
7. Prof. P = 3 votes, Prof. Q = 14 votes, Prof. R = 6 votes and Prof. S = 1.
8. P voted for R, Q voted for S; R voted for Q and S voted for P.
Each professor got one professor vote.

1. Only one of the candidates was from O&Q.
2. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
3. There cannot be more than two candidates from a single department. 
4. Faculty members cannot vote for a candidate from their own department. 
5. P voted for R, Q voted for S; R voted for Q and S voted for P.

1. F&A = 9 members; M&S = 7 members; O&Q = 5 members; B&H = 3 members
2. Only one of the candidates was from O&Q.
3. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
4. There cannot be more than two candidates from a single department.
5. A candidate cannot vote for himself/herself.
6. Faculty members cannot vote for a candidate from their own department.
7. Prof. P = 3 votes, Prof. Q = 14 votes, Prof. R = 6 votes and Prof. S = 1.
8. P voted for R, Q voted for S; R voted for Q and S voted for P.
Each professor got one professor vote.

1. Only one of the candidates was from O&Q.
2. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
3. There cannot be more than two candidates from a single department. 
4. Faculty members cannot vote for a candidate from their own department. 
5. P voted for R, Q voted for S; R voted for Q and S voted for P.

1. F&A = 9 members; M&S = 7 members; O&Q = 5 members; B&H = 3 members
2. Only one of the candidates was from O&Q.
3. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
4. There cannot be more than two candidates from a single department.
5. A candidate cannot vote for himself/herself.
6. Faculty members cannot vote for a candidate from their own department.
7. Prof. P = 3 votes, Prof. Q = 14 votes, Prof. R = 6 votes and Prof. S = 1.
8. P voted for R, Q voted for S; R voted for Q and S voted for P.
Each professor got one professor vote.

1. Only one of the candidates was from O&Q.
2. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
3. There cannot be more than two candidates from a single department. 
4. Faculty members cannot vote for a candidate from their own department.
5. P voted for R, Q voted for S; R voted for Q and S voted for P.

1. F&A = 9 members; M&S = 7 members; O&Q = 5 members; B&H = 3 members
2. Only one of the candidates was from O&Q.
3. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
4. There cannot be more than two candidates from a single department.
5. A candidate cannot vote for himself/herself.
6. Faculty members cannot vote for a candidate from their own department.
7. Prof. P = 3 votes, Prof. Q = 14 votes, Prof. R = 6 votes and Prof. S = 1.
8. P voted for R, Q voted for S; R voted for Q and S voted for P.
Each professor got one professor vote.

1. Only one of the candidates was from O&Q.
2. Every faculty member, including the four candidates, voted for the post. In each department, all the faculty members who were not candidates voted for the same candidate.
3. There cannot be more than two candidates from a single department. 
4. Faculty members cannot vote for a candidate from their own department.
5. P voted for R, Q voted for S; R voted for Q and S voted for P.

The means of the ratings given by R1, R2, R3, R4 and R5 were 3.4, 2.2, 3.8, 2.8 and 3.4 respectively.





(a) R1 awarded a rating of 5 to Waman, as did R2 to Xavier, R3 to Waman and Xavier, and R5 to Vasu.
(b) R1 awarded a rating of 1 to Ullas, as did R2 to Waman and Yusuf, and R3 to Yusuf.

The means of the ratings given by R1, R2, R3, R4 and R5 were 3.4, 2.2, 3.8, 2.8 and 3.4 respectively.





(a) R1 awarded a rating of 5 to Waman, as did R2 to Xavier, R3 to Waman and Xavier, and R5 to Vasu.
(b) R1 awarded a rating of 1 to Ullas, as did R2 to Waman and Yusuf, and R3 to Yusuf.

The means of the ratings given by R1, R2, R3, R4 and R5 were 3.4, 2.2, 3.8, 2.8 and 3.4 respectively.





(a) R1 awarded a rating of 5 to Waman, as did R2 to Xavier, R3 to Waman and Xavier, and R5 to Vasu.
(b) R1 awarded a rating of 1 to Ullas, as did R2 to Waman and Yusuf, and R3 to Yusuf.

The means of the ratings given by R1, R2, R3, R4 and R5 were 3.4, 2.2, 3.8, 2.8 and 3.4 respectively.





(a) R1 awarded a rating of 5 to Waman, as did R2 to Xavier, R3 to Waman and Xavier, and R5 to Vasu.
(b) R1 awarded a rating of 1 to Ullas, as did R2 to Waman and Yusuf, and R3 to Yusuf.

The means of the ratings given by R1, R2, R3, R4 and R5 were 3.4, 2.2, 3.8, 2.8 and 3.4 respectively.





(a) R1 awarded a rating of 5 to Waman, as did R2 to Xavier, R3 to Waman and Xavier, and R5 to Vasu.
(b) R1 awarded a rating of 1 to Ullas, as did R2 to Waman and Yusuf, and R3 to Yusuf.

1. All slots were full - 20 slots each having 10 applicants each. Total 200 applicants
2. The number of US applications was the same in all the slots. The same was true for the other three categories.
3. 50% of the applications were US applications. US Applicants = 100 4. All applicants except Ira, Vijay and Nandini arrived on time.
5. Vijay was called to a counter at 9:25 am.

1. All slots were full - 20 slots X 10 applicants each = 200 applicants 
2. The number of US applications was the same in all the slots. The same was true for the other three categories. US applications = 5 per slot
3. 50% of the applications were US applications. US Applicants = 100 
4. All applicants except Ira, Vijay and Nandini arrived on time. 
5. Vijay was called to a counter at 9:25 am.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
Shengen
At least 3 appointments per slot.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.
6 were processing stuff. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What
does this mean?

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What does this mean?
This means there were no applicants from the UK!!!

Mahira and Osman were scheduled in the 9:30 am slot on that day for that day visa processing in the Others category.
What does this mean?

Mahira and Osman were scheduled in the 9:30 am slot on that day for processing in the Others category.
What does this mean?
At least 2 applicants per slot from Others category.
We have 5 per slot from US, and at least 3 from Shengen and at least 2 from Others.
We have only 10 per slot overall.
Or, in each slot, there are exactly 5 applicants for US visa, 3 for Shengen and 2 for others. O for the UK.

In each slot, there are 5 applicants for the US visa, 3 for Shengen, 2 for others and 0 for the UK
Processing time for US = 10m
Ira = applicant 4 for Shengen Vijay = Applicant 5 
Nandhini = Applicant 6
Mahira & Osman = Applicant nos 5 & 6 for others
Vijay called in at 9:25am.

1. All slots were full - 20 slots each having 10 applicants each. Total 200 applicants
2. The number of US applications was the same in all the slots. The same was true for the other three categories.
3. 50% of the applications were US applications. US Applicants = 100 4. All applicants except Ira, Vijay and Nandini arrived on time.
5. Vijay was called to a counter at 9:25 am.

1. All slots were full - 20 slots X 10 applicants each = 200 applicants 
2. The number of US applications was the same in all the slots. The same was true for the other three categories. US applications = 5 per slot
3. 50% of the applications were US applications. US Applicants = 100 
4. All applicants except Ira, Vijay and Nandini arrived on time. 
5. Vijay was called to a counter at 9:25 am.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
Shengen
At least 3 appointments per slot.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.
6 were processing stuff. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What
does this mean?

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What does this mean?
This means there were no applicants from the UK!!!

Mahira and Osman were scheduled in the 9:30 am slot on that day for that day visa processing in the Others category.
What does this mean?

Mahira and Osman were scheduled in the 9:30 am slot on that day for processing in the Others category.
What does this mean?
At least 2 applicants per slot from Others category.
We have 5 per slot from US, and at least 3 from Shengen and at least 2 from Others.
We have only 10 per slot overall.
Or, in each slot, there are exactly 5 applicants for US visa, 3 for Shengen and 2 for others. O for the UK.

In each slot, there are 5 applicants for the US visa, 3 for Shengen, 2 for others and 0 for the UK
Processing time for US = 10m
Ira = applicant 4 for Shengen Vijay = Applicant 5 
Nandhini = Applicant 6
Mahira & Osman = Applicant nos 5 & 6 for others
Vijay called in at 9:25am.

1. All slots were full - 20 slots each having 10 applicants each. Total 200 applicants
2. The number of US applications was the same in all the slots. The same was true for the other three categories.
3. 50% of the applications were US applications. US Applicants = 100 4. All applicants except Ira, Vijay and Nandini arrived on time.
5. Vijay was called to a counter at 9:25 am.

1. All slots were full - 20 slots X 10 applicants each = 200 applicants 
2. The number of US applications was the same in all the slots. The same was true for the other three categories. US applications = 5 per slot
3. 50% of the applications were US applications. US Applicants = 100 
4. All applicants except Ira, Vijay and Nandini arrived on time. 
5. Vijay was called to a counter at 9:25 am.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
Shengen
At least 3 appointments per slot.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.
6 were processing stuff. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What
does this mean?

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What does this mean?
This means there were no applicants from the UK!!!

Mahira and Osman were scheduled in the 9:30 am slot on that day for that day visa processing in the Others category.
What does this mean?

Mahira and Osman were scheduled in the 9:30 am slot on that day for processing in the Others category.
What does this mean?
At least 2 applicants per slot from Others category.
We have 5 per slot from US, and at least 3 from Shengen and at least 2 from Others.
We have only 10 per slot overall.
Or, in each slot, there are exactly 5 applicants for US visa, 3 for Shengen and 2 for others. O for the UK.

In each slot, there are 5 applicants for the US visa, 3 for Shengen, 2 for others and 0 for the UK
Processing time for US = 10m
Ira = applicant 4 for Shengen Vijay = Applicant 5 
Nandhini = Applicant 6
Mahira & Osman = Applicant nos 5 & 6 for others
Vijay called in at 9:25am.

1. All slots were full - 20 slots each having 10 applicants each. Total 200 applicants
2. The number of US applications was the same in all the slots. The same was true for the other three categories.
3. 50% of the applications were US applications. US Applicants = 100 4. All applicants except Ira, Vijay and Nandini arrived on time.
5. Vijay was called to a counter at 9:25 am.

1. All slots were full - 20 slots X 10 applicants each = 200 applicants 
2. The number of US applications was the same in all the slots. The same was true for the other three categories. US applications = 5 per slot
3. 50% of the applications were US applications. US Applicants = 100 
4. All applicants except Ira, Vijay and Nandini arrived on time. 
5. Vijay was called to a counter at 9:25 am.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
Shengen
At least 3 appointments per slot.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.
6 were processing stuff. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What
does this mean?

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What does this mean?
This means there were no applicants from the UK!!!

Mahira and Osman were scheduled in the 9:30 am slot on that day for that day visa processing in the Others category.
What does this mean?

Mahira and Osman were scheduled in the 9:30 am slot on that day for processing in the Others category.
What does this mean?
At least 2 applicants per slot from Others category.
We have 5 per slot from US, and at least 3 from Shengen and at least 2 from Others.
We have only 10 per slot overall.
Or, in each slot, there are exactly 5 applicants for US visa, 3 for Shengen and 2 for others. O for the UK.

In each slot, there are 5 applicants for the US visa, 3 for Shengen, 2 for others and 0 for the UK
Processing time for US = 10m
Ira = applicant 4 for Shengen Vijay = Applicant 5 
Nandhini = Applicant 6
Mahira & Osman = Applicant nos 5 & 6 for others
Vijay called in at 9:25am.

1. All slots were full - 20 slots each having 10 applicants each. Total 200 applicants
2. The number of US applications was the same in all the slots. The same was true for the other three categories.
3. 50% of the applications were US applications. US Applicants = 100 4. All applicants except Ira, Vijay and Nandini arrived on time.
5. Vijay was called to a counter at 9:25 am.

1. All slots were full - 20 slots X 10 applicants each = 200 applicants 
2. The number of US applications was the same in all the slots. The same was true for the other three categories. US applications = 5 per slot
3. 50% of the applications were US applications. US Applicants = 100 
4. All applicants except Ira, Vijay and Nandini arrived on time. 
5. Vijay was called to a counter at 9:25 am.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.

On a particular day, Ira, Vijay and Nandini were scheduled for Schengen visa processing in that order.
Shengen
At least 3 appointments per slot.
They had a 9:15 am slot but entered the VPO at 9:20 am. When they entered the office, exactly six out of the ten counters were either processing applications, or had finished processing one and ready to start processing the next.
6 were processing stuff. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What
does this mean?

6 were processing stuff at 9 20. All 4 US counters should have been processing. Since Ira, Vijay and Nandini could not go and join, the two Shengen counters should also have been processing.
The processing time for an application is the same within each category. But it may vary across the categories. Each US and UK application requires 10 minutes of processing time.
So, at 920 technically UK counters should have been processing an applicant but they are not doing this. What does this mean?
This means there were no applicants from the UK!!!

Mahira and Osman were scheduled in the 9:30 am slot on that day for that day visa processing in the Others category.
What does this mean?

Mahira and Osman were scheduled in the 9:30 am slot on that day for processing in the Others category.
What does this mean?
At least 2 applicants per slot from Others category.
We have 5 per slot from US, and at least 3 from Shengen and at least 2 from Others.
We have only 10 per slot overall.
Or, in each slot, there are exactly 5 applicants for US visa, 3 for Shengen and 2 for others. O for the UK.

In each slot, there are 5 applicants for the US visa, 3 for Shengen, 2 for others and 0 for the UK
Processing time for US = 10m
Ira = applicant 4 for Shengen Vijay = Applicant 5 
Nandhini = Applicant 6
Mahira & Osman = Applicant nos 5 & 6 for others
Vijay called in at 9:25am.

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
We have entered the maximum possible neighbour count outside the box in red. Note that this is the max possibly neighbour count and not actual neighbour count.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
2. Row-1 has two occupied houses, one in each block.
3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be?
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours.
1. If it were E2 with zero neighbours, then D2 and F2 should be empty. This means D1 and F1 should be occupied (constraint 4). This is not possible as Row 1 has only one occupied house in block YY.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. Either F1 or D1 should be vacant. If F1 were vacant, it would have a maximum quoted price of 10 + 3 = 13. This is not possible.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency ) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
We have entered the maximum possible neighbour count outside the box in red. Note that this is the max possibly neighbour count and not actual neighbour count.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
2. Row-1 has two occupied houses, one in each block.
3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be?
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours.
1. If it were E2 with zero neighbours, then D2 and F2 should be empty. This means D1 and F1 should be occupied (constraint 4). This is not possible as Row 1 has only one occupied house in block YY.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. Either F1 or D1 should be vacant. If F1 were vacant, it would have a maximum quoted price of 10 + 3 = 13. This is not possible.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency ) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
We have entered the maximum possible neighbour count outside the box in red. Note that this is the max possibly neighbour count and not actual neighbour count.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
2. Row-1 has two occupied houses, one in each block.
3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be?
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours.
1. If it were E2 with zero neighbours, then D2 and F2 should be empty. This means D1 and F1 should be occupied (constraint 4). This is not possible as Row 1 has only one occupied house in block YY.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. Either F1 or D1 should be vacant. If F1 were vacant, it would have a maximum quoted price of 10 + 3 = 13. This is not possible.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency ) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
We have entered the maximum possible neighbour count outside the box in red. Note that this is the max possibly neighbour count and not actual neighbour count.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
2. Row-1 has two occupied houses, one in each block.
3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be?
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours.
1. If it were E2 with zero neighbours, then D2 and F2 should be empty. This means D1 and F1 should be occupied (constraint 4). This is not possible as Row 1 has only one occupied house in block YY.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. Either F1 or D1 should be vacant. If F1 were vacant, it would have a maximum quoted price of 10 + 3 = 13. This is not possible.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency ) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
The road adjacency value of a house is the number of its sides adjacent to a road. For example, the road adjacency values of C2, F2, and B1 are 2, 1, and 0, respectively. The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
The neighbour count of a house is the number of sides of that house adjacent to occupied houses in the same block. For example, E1 and C1 can have the maximum possible neighbour counts of 3 and 2, respectively.
The base price of a vacant house is Rs. 10 lakhs if the house does not have a parking space, and Rs. 12 lakhs if it does. The quoted price (in lakhs of Rs.) of a vacant house is calculated as (base price) + 5 × (road adjacency value) + 3 × (neighbour count).

Some of the houses are occupied. The remaining ones are vacant and are the only ones available for sale.
We have entered the road adjacency numbers inside the boxes in purple.
We have entered the maximum possible neighbour count outside the box in red. Note that this is the max possibly neighbour count and not actual neighbour count.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
2. Row-1 has two occupied houses, one in each block.
3. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be?
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. - Which house could this be? A1, B1 cannot reach up to Rs. 24 lakhs. Nor can C1 or A2. C2 price should be 10/12 + 10 + 3 × (Neighbour count). This can be 20/22 or 23/25 or 26/28. So, B2 should be the one that costs Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. 4. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. Either E1 with base price 12 and one neighbour or E2 with base price 10 and zero neighbours.
1. If it were E2 with zero neighbours, then D2 and F2 should be empty. This means D1 and F1 should be occupied (constraint 4). This is not possible as Row 1 has only one occupied house in block YY.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. Either F1 or D1 should be vacant. If F1 were vacant, it would have a maximum quoted price of 10 + 3 = 13. This is not possible.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency ) + 3 × (Neighbour Count)

1. The maximum quoted price of a house in Block XX is Rs. 24 lakhs. So, B2 comes with no parking lot and 3 neighbours.
2. The minimum quoted price of a house in block YY is Rs. 15 lakhs, and one such house is in Column-E. E1 should have base price 12 and one neighbour. D1 is vacant, F1 is occupied.
3. Row-1 has two occupied houses, one in each block.
4. Both houses in Column-E are vacant. Each of Column-D and Column-F has at least one occupied house.
5. There is only one house with parking space in Block YY.
Quoted Price = 10L/12L + 5 × (Road Adjacency) + 3 × (Neighbour Count)